Problems with double variables

code questions
1

Hello!
I'm currently programming a new project of mine and ran into the following issue.
When I perform the calculation (20/40)/2, the result is not the expected 0.25, but rather 0.
I've managed to recreate this issue in the following script.
void main()
{
double x=(20/40)/2;
alert("Result", x);
}
If you have any ideas about fixing this problem, please tell me, since I need a exact output for my program.
I also tryed it with simple floats, that didn't work either though.
Regards
Taurus Fan

2

double x = tinyexpr("(20 / 40) / 2");

3

Thanks a lot, now it works. :slight_smile:

4

It's because the expression is being interpreted as all integers, and thus integer division (with truncation) is being used. If you make one of the operands look like a double, the whole expression will be upward cast to it and evaluated there.
double x=(20/40)/2.0; might be enough, the .0 indicating that 2.0 is a double. 2.0f is a float, I think. If not, because of the parentheses, you might have to put a .0 on one of the numbers inside it too.

5

Hello!
Thanks, that helps. I put a .0 behind one of the numbers inside the brackets and it worked.
Regards
Taurus Fan